Jonathan Bales is a special contributor to SportsDayDFW.com. He’s the founder of The DC Times and writes for DallasCowboys.com and the New York Times. He’s also the author of Fantasy Football for Smart People. He can be reached at
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After a thrilling overtime victory over the Pittsburgh Steelers, the Dallas Cowboys sit in a three-way tie for first place atop the NFC East. With two games remaining in the 2012 season, the Cowboys control their own destiny toward the postseason. So what are their odds of winning the NFC East? Let’s take a look at the remaining schedules for each squad:
Cowboys: New Orleans, @Washington
Redskins: @Eagles, Cowboys
Giants: @Ravens, Eagles
Like I did in last week’s breakdown of the Cowboys’ playoff chances, I’ll assume the Cowboys, Giants, and Redskins all possess a 50 percent chance to win each remaining contest—likely not far from reality. Since the Cowboys still play the Redskins in Week 17, one of those two teams is extremely likely to win the NFC East. Here’s why. . .
There are four possible outcomes over the Cowboys’ final two contests: WW, LW, WL, and LL. The first outcome—if the ‘Boys win both games—would win them the NFC East because, even if the Giants win both of their two remaining games, the Cowboys will trump them on a division tiebreaker. The last scenario would obviously knock Dallas out of the playoffs, as would the third.
If the Cowboys lose to New Orleans and beat Washington in Week 17, they can still get into the playoffs if the Giants lose at least one of their two remaining games. In that case, the Cowboys would either be tied with the Giants at 9-7 or be in a tie with both the Giants and Redskins at 9-7 (depending on the Redskins’ fate in Week 16). Per NFL.com, head-to-head and three-team tiebreaking rules within the division are as follows:
1.Head-to-head (best won-lost-tied percentage in games between the clubs).
2.Best won-lost-tied percentage in games played within the division.
3.Best won-lost-tied percentage in common games.
Since the Cowboys will have a better division record than the Giants if they win in Washington, they’d get in if the two teams end up tied. If all three teams have the same record, Dallas would also win that tiebreaker due to a superior record in common games.
Thus, the Cowboys’ chances of making the playoffs are 25 percent—the odds of winning both remaining games—plus the probability of losing in New Orleans, winning in Washington, and seeing the Giants lose at least one of their remaining games. Assuming the Giants have a 50 percent win probability, the odds of them losing just one more game (at a minimum) are 75 percent. Factoring that into the equation gives us the final probability of Dallas winning the NFC East—43.8 percent.
Not bad after a 3-5 start, huh?